10 Question-Answer on periodic motion and S.H.M.
1. If in the equation y= 5 sin(0.05t + 0.05) , y represents the displacement at the instant t, then which one of the following gives the frequency?
(A) 5
(B) 0.05
(C) 0.05/2π
(D) 2π × 0.05
Ans: (C)
2. The displacement of the particle is represented by y = 10 sin (5t + θ). The period of oscillation is:
(a) 2π/5s
(b) 5/2πs
(c) π/5s
(d) 5/πs
Ans: (a)
3. A body is executing S.H.M. When its displacement from the mean position is 4 cm and 5 cm, it has velocities 10 m/s and 8 cm/s respectively. Its periodic time t
(a) π/2s
(b) π s
(c) 3π/2 s
(d) 2πs
Ans: (b)
4. A particle is simultaneously subjected to two collinear S.H.Ms. For the resultant amplitude to be maximum, the phase diff. between them should be:
(a) Zero
(b) π/2 s
(c) π s
(d) 2π s
Ans: (a, d)
5. A particle is acted simultaneously by two mutually perpendicular S.S.Ms;
X = a cos ωt and y = a sin ωt. The trajectory of motion of the particle will be:
(a) An ellipse
(b) A parabola
(c) A circle
(d) A hyperbola
6. A particle is executing S.H.M. when its acceleration increases, its time period
(a) Decreases
(b) Increases
(c) Remains same
(d) Becomes half
Ans: (c)
7. A particle in S.H.M. Then the graph of velocity as a function of displacement is:
(a) A straight line
(b) A circle
(c) An eclipse
(d) A hyperbola
Ans: ( c)
8. A particle is executing S.H.M. along a straight line so that its period is 12 sec. the time it takes in traversing a distance equal to half its amplitude from its equilibrium is:
(a) 6 sec
(b) 4 sec
(c) 3 sec
(d) 1 sec
Ans:( d)
9. A particle of mass 1 kg is moving in S.H.M. with an amplitude 0.02 m and a frequency of 60 Hz. The maximum force in Newton acting on the particle is:
(a) 188 π2
(b) 144 π2
(c) 288 π2
(d) None of the above
Ans: ( c)
10. The acceleration of a particle in S.H.M. is
(a) Always constant
(b) Maximum at extreme position
(c) Maximum at equilibrium position
(d) Always zero
Ans: (b)