Friday, November 13, 2020
Examples of principles of communication
Example: T.V. transmission tower at a particular station has a height of 144 m. Radius of the earth = 6400 km.
(a) What is its coverage range?
(b) How much population is covered by transmission, if the average population density around the tower is 1000/km2?
(c) By how much the height of tower be increased to double its coverage range.
Solution:
Here: h=144 m; R=6400 km= 6.4 × 106 m; ρ = 1000km-2
(a) Coverage range, d = √(2hr)
=√(2×144×6.4×106)
=42.933 km
(b) Population covered= population density × area
= ρ×πd2=1000×(22/7)×(42.933)2
=57.93 lakh
(c) d’ =√(2h’R)=2d =2√(2hr) or 4h=4 ×144=576 m
Increase in height of tower = h’-h = 576-144 = 432 m