Example of heat and thermodynamics
Example: Ice in a cold storage melts at a rate of 2.5 kg/hour. When the external temperature is 27˚ C. Find the minimum power output of the motor of the refrigerator which just prevents the ice from melting. Latent heat of fusion of ice = 80 cal/g.
Solution: To prevent melting of ice, heat energy is to be taken out.
Heat energy to be removed/hour mL = 2.5 × 103 ×80 cal/hour
Heat energy to be removed/sec Q2 =( 2.5 × 103 × 80 )/( 60 × 60) =55.55 cal/s
= 55.55 × 4.2 J/s =233.3 J/s
As T1 = 27˚ C = 27 + 273 = 300 K
And T2 = 0˚ C = 0+ 273 = 273 K
Coefficient of performance, β = T2 / (T1 – T2)=273/(300-273)=273/27
As β = Q2 /W
W = Q2 / β = 233.3/(273/27)= 27 × 233.3/273
W = 6300.0
273= 23.1 watt
This is the minimum power output of the motor