Example of motion in one dimension
Solution:
Let v km/h be the constant speed with which the buses ply between the towns A and B.
The relative speed of the bus, from A to B (i.e. in the direction of motion of cyclist) with respect to the cyclist = (v -20)km/h.
The relative speed of the bus, from B to A with respect to the cyclist =(v+20)km/h.
The distance travelled by the bus in the time T hour =vT
As per question : vT/(v-20)=18/60 or 60vT=18v-360 …………(i)
And vT/(v+20)= 6/60 or 60vT = 6v + 120 ………………….(ii)
From (i) and (ii), we have
18v-360 = 6v+120
12v=480 or v= 40km/h.
Putting the value in (i) we have,
60 × 40 × T = 18 × 40 – 360 = 360 or T = 360h/60×40 = 9 min.
Ans . 9 min is the period T of the bus service